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A ball thrown vertically upward returns ...

A ball thrown vertically upward returns to its starting point in 4 s. Find its initial speed.

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To solve the problem of finding the initial speed of a ball thrown vertically upward that returns to its starting point in 4 seconds, we can follow these steps: ### Step 1: Understand the Motion The ball is thrown vertically upward and returns to the starting point. The total time taken for this motion is given as 4 seconds. This time includes both the upward and downward journey. ### Step 2: Use the Concept of Time of Flight The time of flight (T) for an object thrown vertically upward and returning to the same point is given by the formula: \[ T = \frac{2u}{g} \] ...
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Knowledge Check

  • A ball thrown vertically upwards returns to the thrower in 20 second. Calculate the velocity with which it was thrown and the maximum height attained by the ball. Take g = 10 m//s^(2) .

    A
    100 m/s, 200 m
    B
    10 m/s, 500 m
    C
    100 m/s, 500 m
    D
    None

  • A ball thrown vertically upwards with an initial velocity of 1.4 m//s. The total displcement of the ball is

    A
    `22.4cm`
    B
    zero
    C
    `44.8m`
    D
    `33.6m`

  • A ball is thrown vertically upward with speed 10 m//s and it returns to the ground with speed 8 m//s . A constant air resistance acts. The minimum height attained by the ball is

    A
    `5 m`
    B
    `4.5 m`
    C
    `3.5 m`
    D
    `4.1 m`

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    A ball thrown vertically up retruns to the thrower after 6 s. find the velocity with which it was thrown and its position after 4 s.

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    (a) A ball is thrown vertically upward with speed 10 m//s and it returns to the ground with speed 8 m//s . Find the maximum height attained by the ball. (b) A ball is thrown vertically upward and if air resistance is half of weight of the ball, find the ratio of time of ascent and time of descent. (C) Two balls A and B (m_(A) = 2 m_(B) = 2 m) are thrown vertically upward. If air resistance is mg//2 , find ratio of maximum height attained by them.

    In the following problems the air resistance is constant (air resistance always opposes the motion). (a) A ball is thrown vertically upward. If time of ascent is t_(1) and time of descent is t_(2) , which time is greater ? (b) A ball is thrown vertically upward with speed u and on returning to the ground, its speed is v_(0) . Which speed is greater ? (c) Two balls A and B (m_(A) gt m_(B)) are thrown vertically upward with same speed. Which ball A or B (heavier or lighter) wil attain greater height ?

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