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A ball is dropped from the top of a buil...

A ball is dropped from the top of a building. The ball takes `0.50`s to fall past the 3m length of a window, which is some distance below the top of the building.
(a) How fast was the ball going as it passed the top of the window?
(b) How far is the top of the window from the point at which the ball was dropped?
Assume acceleration g in free fall due to gravity to be `10 m//s^(2)` downwards.

Text Solution

Verified by Experts

The velocities `v_(A)` at the top and `v_(B)` at the bottom of the window are related by the following equations
`v_(av) =(v_(A) +v_(B))//2=3//0.5 =6 m//s`
so, `v_(A) +v_(B) =12" m/s "and v_(B) -v_(A) =4.9" m/s"`
Eliminating between these two expressions we get `v_(A) =3.55" m/s"`
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