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A body is projected horizontally from th...

A body is projected horizontally from the top of a cliff with a velocity of `9.8ms^(-1)`. What time elapes before horizontal and vertical velocities become equal ? Take `g=9.8 ms^(-2)`.

Text Solution

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Let t be the time taken after which horizontal and vertical velocities become equal.
For horizontaI motion:
`u_(x) =9.8" ms"^(1), a_(x) =0`
Using `v_(x) =u_(x) +a_(x)t`, we get
`v_(x) =9.8" ms"^(-1)" …(i)"`
For verticaI motion:
`u_(y) =0, a_(y) =g =9.8" ms"^(-2)`
Using `v_(y) =u_(y) + a_(y) t`, we get
`v_(y) =(9.8 t)" ms"^(-1)" ....(ii)"`
Since `v_(x) =v_(y)`
`? 9.8=9.8t" or "t=1s`
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