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Two balls are projected from the same po...

Two balls are projected from the same point with such a speed that both reach the same point on ground at a distance of `19.6 sqrt(3) m` from the point of projection. If one of the particles is projected at an angle of `30^(@)` with the ground, then calculate the time of flight of the second ball.

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To solve the problem, we need to find the time of flight of the second ball that is projected from the same point as the first ball, which is projected at an angle of \(30^\circ\) with the ground. Both balls reach the same point on the ground at a distance of \(19.6 \sqrt{3} \, m\). ### Step-by-Step Solution: 1. **Identify the known values**: - Range \( R = 19.6 \sqrt{3} \, m \) - Angle of projection for the first ball \( \theta_1 = 30^\circ \) - Gravitational acceleration \( g = 9.8 \, m/s^2 \) ...
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