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A stone of mass 0.1 kg tied to one end o...

A stone of mass 0.1 kg tied to one end of a string lm long is revolved in a horizontal circle at the rate of `(10)/(pi)" rev/s"`. Calculate the tension in the string.

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To solve the problem, we need to calculate the tension in the string when a stone of mass 0.1 kg is revolved in a horizontal circle at a rate of \( \frac{10}{\pi} \) revolutions per second. ### Step-by-Step Solution: 1. **Identify the given values:** - Mass of the stone, \( m = 0.1 \, \text{kg} \) - Length of the string (radius of the circular path), \( r = 1 \, \text{m} \) - Rate of revolution, \( f = \frac{10}{\pi} \, \text{rev/s} \) ...
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