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A particle moves in a circle of radius 2...

A particle moves in a circle of radius 20 cm. Its linear speed is given by `v = (3t^(2) +5t)` where t is in second and v is in m/s. Find the resultant acceleration at t = 1s.

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To solve the problem step by step, we will follow the outlined process to find the resultant acceleration of the particle moving in a circular path. ### Step 1: Identify the Given Information - Radius of the circular path, \( r = 20 \) cm = \( 0.2 \) m (conversion from cm to m) - Linear speed equation: \( v(t) = 3t^2 + 5t \) (in m/s) ### Step 2: Calculate the Tangential Acceleration Tangential acceleration (\( a_t \)) is the rate of change of linear velocity with respect to time. We can find it by differentiating the velocity function with respect to time \( t \). ...
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