A boy standing on a stationary lift (open from above) throws a ball upwards with the maximum initial speed he can , equal to `49" ms"^(–1)`, how long does the ball take to return to his hands.?

Explanation

To solve the problem of how long it takes for the ball to return to the boy's hands after being thrown upwards with an initial speed of \(49 \, \text{m/s}\), we can use the equations of motion. Here’s a step-by-step solution:

### Step 1: Identify the known values
- Initial speed of the ball, \(u = 49 \, \text{m/s}\)
- Acceleration due to gravity, \(g = 9.8 \, \text{m/s}^2\) (acting downwards)

### Step 2: Use the equation of motion
We can use the equation of motion that relates displacement, initial velocity, acceleration, and time:
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