Home
Class 12
PHYSICS
The position co-ordinates of the centre ...

The position co-ordinates of the centre of mass of a system of three particles of equal masses which are placed on the verctices of an equilateral triangle of a side a are shown. Locate centre mass?

Text Solution

Verified by Experts

`x_(cm)=(m(0)+m(a)+m(a/2))/3_m` `x_(cm)=(3m1/2)/(3m)=a/2` `y_(cm)=(m(0)+m(0)+m((sqrt3)/2a))/(3m)=a/(2sqrt3)` co-ordinates of the centre of mass of the system are`(a/2,a/(2sqrt3))`.
Promotional Banner

Similar Questions

Explore conceptually related problems

Locate the centre of mass of a system of three particles 1.0 kg, 2.0 kg and 3.0 kg placed at the corners of an equilateral traingular of side 1m.

The gravitational potential energy of a system of three particles of mass m each kept at the vertices of equilateral triangle of side x will be

Three particles of equal mass 'm' are situated at the vertices of an equilateral triangle of side L . The work done in increasing the side of the triangle to 2L is

Three masses 3,4 and 5 kg are located at the corners of an equilateral triangle of side 1m. Locate to centre of mass of the system.

Three particle each of mass m are placed at the corners of equilateral triangle of side l Which of the following is/are correct ?

What is the position vector of centre of mass of two particles of equal masses ?

Three particles of masses 1 kg, (3)/(2) kg, and 2 kg are located the vertices of an equilateral triangle of side a . The x, y coordinates of the centre of mass are.

The centre of masses of three particles of mass m_(1) = m_(2)=m_3 = 1 kg at the corners of an equilateral triangle of side 1 m will be -

Four particles of masses m, m, 2m and 2m are placed at the corners of a square of side a, as shown in fig. Locate the centre of mass.