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The radius of gyration of a solid shaper...

The radius of gyration of a solid shapere of radius r about a certain axis is r. The distance of this axis from the centre of the shpere is

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`I=I_(CM)+Md^2` (parallel axis therorem) `Mk^2=2/5MR^2+Md^2` (But k+R) `rArr MR^2=2/5MR^2+Md^2rArrd=sqrt0.6R`.
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