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Moment of inertia of a disc about an axi...

Moment of inertia of a disc about an axis which is tangent and parallel to its plane is I . Then the moment of inertia of disc about a tangent, but perpendicular to its plane will be

A

`6/5I`

B

`3/4I`

C

`3/2I`

D

`5/4I`

Text Solution

Verified by Experts

The correct Answer is:
A
`I_1=(1/4mr^2)+mr^2=(5mr^2)/4=I` `rArrI_2=1/2mr^2+mr^2=3/2mr^2=(6I)/5`
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