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Two men support a uniform horizontal bea...

Two men support a uniform horizontal beam at its two ends, if one of them suddenly lets go, the force exerted by the beam on the other man will

A

remain unaffected

B

increase

C

decrease

D

become unequal to the force exerted by him on the beam

Text Solution

Verified by Experts

The correct Answer is:
3
When the beam is supported at A and B, the force exerted by each man = mg/2. When the support at B is withdrawn, taking torque about A,`tau=(mg)1/2=Ialpha=((ml^2)/3)alpha` or `alpha=(3g)/(2l)`The instantaneous linear acceleration of the centre of mass is `a_(CM)=(alpha)(AC)=((3g)/21)1/2=(3g)/4`Let N = force exerted on the beam at A.`because mg-N=ma_(CM)=m((3g)/4)` or N=1/4mg.`
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