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The potential difference applied to an X...

The potential difference applied to an X-ray tube is 5k V and the current through it is 3.2 mA. Then, the number of electrons striking the target per second is. (a) `2xx10^16` (b) `5xx10^6` (c ) `1xx10^17` (d) `4xx10^15`.

A

`2xx10^(16)`

B

`5xx10^(6)`

C

`1xx10^(17)`

D

`4xx10^(15)`

Text Solution

Verified by Experts

The correct Answer is:
A
I=`(q)/(t)`=`("ne")/(t)` `rArr` n=`(it)/(e)`=`(3.2xx10^(-3)xx1)/(1.6xx10^(-19))`=`2xx10^(16)`
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