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A beam of electrons moving at a speed of...

A beam of electrons moving at a speed of `10^(6)m//s` along a line produces a current of `1.6xx10^(-6)` A. The number of electrons in the 1 metre of the beam is

A

`10^(6)`

B

`10^(7)`

C

`10^(13)`

D

`10^(19)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the number of electrons in a 1-meter beam of electrons moving at a speed of \(10^6 \, \text{m/s}\) that produces a current of \(1.6 \times 10^{-6} \, \text{A}\), we can follow these steps: ### Step 1: Calculate the time taken to travel 1 meter Using the formula for time: \[ \text{Time} = \frac{\text{Distance}}{\text{Speed}} \] Given that the distance is 1 meter and the speed is \(10^6 \, \text{m/s}\): \[ \text{Time} = \frac{1 \, \text{m}}{10^6 \, \text{m/s}} = 1 \times 10^{-6} \, \text{s} \] ### Step 2: Relate current to charge and time The current \(I\) can be expressed in terms of charge \(Q\) and time \(t\): \[ I = \frac{Q}{t} \] Rearranging this gives: \[ Q = I \cdot t \] Substituting the values of current and time: \[ Q = (1.6 \times 10^{-6} \, \text{A}) \cdot (1 \times 10^{-6} \, \text{s}) = 1.6 \times 10^{-12} \, \text{C} \] ### Step 3: Calculate the number of electrons The charge of a single electron \(e\) is approximately \(1.6 \times 10^{-19} \, \text{C}\). The total charge \(Q\) can also be expressed as: \[ Q = n \cdot e \] where \(n\) is the number of electrons. Rearranging gives: \[ n = \frac{Q}{e} \] Substituting the values: \[ n = \frac{1.6 \times 10^{-12} \, \text{C}}{1.6 \times 10^{-19} \, \text{C}} = 10^7 \] ### Conclusion The number of electrons in 1 meter of the beam is: \[ n = 10^7 \] ---

To find the number of electrons in a 1-meter beam of electrons moving at a speed of \(10^6 \, \text{m/s}\) that produces a current of \(1.6 \times 10^{-6} \, \text{A}\), we can follow these steps: ### Step 1: Calculate the time taken to travel 1 meter Using the formula for time: \[ \text{Time} = \frac{\text{Distance}}{\text{Speed}} \] Given that the distance is 1 meter and the speed is \(10^6 \, \text{m/s}\): ...
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