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A wire of resistance 0.5 omega m^(-1) is...

A wire of resistance `0.5 omega m^(-1)` is bent into a circle of radius `1m`. The same wire is connected across a diameter `AB` as shown in fig. The equivalent resistance is

A

`pi`ohm

B

`pi(pi+2)ohm`

C

`pi//(pi+4)ohm`

D

`(pi+4)ohm`

Text Solution

Verified by Experts

The correct Answer is:
C
`(1)/(R_(AB))`=`(1)/(0.5pi)+(1)/(1)+(1)/(0.5pi)` `rArr` `R_(AB)=(pi)/((pi+4))Omega`
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