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In an experiment to measure the internal...

In an experiment to measure the internal resistance of a cell by potentiometer, it is found that the balance point is at a length of `2 m` when the cell is shuntedd by a `5 Omega` resistance, and is at a length of `3 m` when the cell is shunted by a `10 Omega` resistance. The internal resistance of the cell is, then

A

`1.5Omega`

B

`10Omega`

C

`15Omega`

D

`1Omega`

Text Solution

Verified by Experts

The correct Answer is:
B
By using r=`((l_(1)-l_(2))/(l_(2)))r` `rArr` r=`((i_(2)-2)/(2))xx5`.......(i)
and r=`((l_(3)-3)/(3))xx10`.....(ii)
On "solving" (i) and (ii) r = `10Omega`.
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