Three identical cells, each of emf 2 V and internal resistance `0.2Omega` are connected in series to an external resistor of `7.4Omega`. Calculate the current in the circuit.

Four cells, each of emf E and internal resistance r, are connected in series across an external resistance reverse. Then, the current in the external circuit is

4 cells each of emf 2 V and internal resistance of 1Omega are connected in parallel to a load resistor of 2Omega . Then the current through the load resistor is

Three identical cells of emf 2 V and internal resistances 0.20 Omega are connected in series. The combination is further connected to an external resistor of 6 Omega . Calculate the current through 6 Omega resistor.

Three identical cells , each having an emf 1.5 V and a constant internal resistance 2.0 omega , are connected in series with a 4.0 omega resistor R , first as in circuit (i) , and second as in circuit (ii) . Then ( power in R in circuit (i))/( Power in R in circuit (ii)) =

A set of 4 cell each of emf 2V and internal resistance 1.5 Omega are connected across an external load of 10 Omega with 2 rows, two cells in eacg row. Calculate the current in each row and potential difference across 10 Omega

A cell of e.m.f. 2 V and internal resistance 2Omega and an external resistance 18Omega forms closed circuit. The current through the circuit is