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A beam of protons moving with a velocity...

A beam of protons moving with a velocity of `4 xx 10^(5) m/s` enetrs a uniform magnetic field of 0.3 T at an angle of 60◦ with the magnetic field. What is the radius of the helical path described by the proton beam?`[m_p=1.67 xx 10^(-27) kg` and the charge on the proton`=1.6 xx 10^(-19)`C]

Text Solution

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`:.`Pitch of the helix P=`(Vcos thetha) (T)`
`=V cos thetha 2pim/qB =(4xx10^(5)xx0.5)(2pi)(1.67xx10^(-27))/(1.6 xx 10^(-19)) (0.3) =4.372 xx 10^(-2)`m
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