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A horizontal rod of mass 10g and length ...

A horizontal rod of mass `10g` and length `10cm` is placed on a smooth plane inclined at an angle of `60^@` with the horizontal with the length of the rod parallel to the edge of the inclined plane. A uniform magnetic field induction B is applied vertically downwards. If the current through the rod is `1*73ampere`, the value of B for which the rod remains stationary on the inclined plane is

Text Solution

Verified by Experts

The various forces acting on rod and their components. Since the rod is stationary, so balance the forces.
`F_(M)cos theta = mg sin g theta (theta = 60^(@))`
`IBlcos theta= mg sin theta `
`rArr IBl=mg tan theta``rArr B=mg tan theta/Il = 10xx10^(-3)xx10xxsqrt(3)/1.73xx10xx10^(-2)=1T.`
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