Home
Class 12
PHYSICS
A rectangular coil 20cmxx20cm has 100 tu...

A rectangular coil `20cmxx20cm` has `100` turns and carries a current of `1 A`. It is placed in a uniform magnetic field `B=0.5 T` with the direction of magnetic field parallel to the plane of the coil. The magnitude of the torque required to hold this coil in this position is

A

Zero

B

200N-m

C

2N-m

D

10N-m

Text Solution

Verified by Experts

The correct Answer is:
3
Promotional Banner

Similar Questions

Explore conceptually related problems

A coil carrying electric current is placed in uniform magnetic field

A circular coil of 20 turns each of radius 10 cm and carrying a current of 5 A is placed in a uniform magnetic field of induction 0.10 T normal to the plane of the coil?

When a current carrying coil is placed in a uniform magnetic field with its magnetic moment anti-parallel to the field.

A circular coil of 20turns and radius 10cm carries a current of 5A . It is placed in a uniform magnetic field of 0*10T . Find the torque acting on the coil when the magnetic field is applied (a) normal to the plane of the coil (b) in the plane of coil. Also find out the total force acting on the coil.

A coil of radius 2 cm and 500 turns, carries of a current of 2A. It is placed in a uniform magnetic field of induction 0.5T. What is the torque acting on the coil if theta=30◦ ?

A current i flows in a circular coil of radius r . If the coil is placed in a uniform magnetic field B with its plane parallel to the field, magnitude of the torque that acts on the coil is

A circular coil of 100turns radius 10cm, carries a current of 5A. It is suspended vertically in a uniform horizontal magnetic field of 0.5T and the field lines make an angle of 60^(@) with the plane of the coil. The magnitude of the torque that must be applied on it to prevent it from turning is