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An alternating voltage of 220 volts r.m....

An alternating voltage of `220` volts `r.m.s.` at a freqency of `40` cycles/sec is supplied to a circuit containing a pure inductance of `0.01 H` and a pure resistance of `6 ohms` in series.Calculate (i)the current , (ii)potential diffence across the resistance, (iii)potential difference across the inductance, (iv)the time lag, (v)power factor.

Text Solution

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Phase angle`phi=tan^(-1)(omegaL)/(R)`
`thereforephi=tan^(-1)(0.4189)=22^(@)46’`
  Now time lag=`(phi)/(360)xxT=(phi)(360)xx(1)/(phi)=(22^(@)46)/(360xx40)`=0.01579second
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