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For the circuit shown in fig, current in...

For the circuit shown in fig, current in inductance is 0.8A while that in capacitance is 0.6 A. What is the current drawn from the source?

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In this ac circuit e = e_(0)sint is applied across an inductance and capacitance in parallel, current in inductance will lag the applied voltage while across the capacitor will lead,
and so` I__(L)=(V)/(X_(L)) sin(0megat+((pi)/(2)= 0.8 cosomegat`
`I_(C) = (V)/(X_(L)sin(omegat+(pi)/(2)) = 0.6 cos omegat`
So the current drawn from the source,` `I=I_(L) +I_(c) =-2 cos omegat, i.e., |I_(0) = 0.2 A`
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