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A thin semi-circular conducting ring of ...

A thin semi-circular conducting ring of radius R is falling with its plane verticle in horizontal magnetic induction `(vec B)`. At the position MNQ the speed of the ring is v, and the potential difference developed across the ring is

A

zero

B

`BvR^(2)/2` and M is at higher potential

C

`(W_(1))/(W_(2))=4`

D

`(W_(1))/(W-(2)=(1)/(16))`

Text Solution

Verified by Experts

The correct Answer is:
4
The induced emf as given by Faraday.s law of induction is`E=-Blv`
`l=2R`
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