In L-R circuit, resistance is `8Omega` and inductive reactance is `6Omega` then impedance is:

Options

A. `2Omega`
B. `14Omega`
C. `4Omega`
D. `10Omega`

Answer

To find the impedance (Z) in an L-R circuit where the resistance (R) is given as 8 Ohms and the inductive reactance (XL) is given as 6 Ohms, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the given values**:
- Resistance (R) = 8 Ohms
- Inductive Reactance (XL) = 6 Ohms

2. **Understand the formula for impedance**:
The impedance (Z) in an L-R circuit can be calculated using the Pythagorean theorem since the resistance and the inductive reactance are perpendicular to each other in the impedance triangle:
\[ Z = \sqrt{R^2 + X_L^2} \]

3. **Substitute the given values into the formula**:
\[ Z = \sqrt{(8)^2 + (6)^2} \]

4. **Calculate the squares**:
- \(8^2 = 64\)
- \(6^2 = 36\)

5. **Add the squares**:
\[ Z = \sqrt{64 + 36} \]
\[ Z = \sqrt{100} \]

6. **Calculate the square root**:
\[ Z = 10 \text{ Ohms} \]

### Final Answer:
The impedance of the circuit is **10 Ohms**.

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