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Find the minimum and maximum angle of de...

Find the minimum and maximum angle of deviation for a prism with angle `A = 60^(@)` and `mu = 1.5`

Text Solution

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The angle of minimum deviation occurs when i = e and `r = r_(2)` and is given by
`mu=(sin((A+delta_(m))/2))/(sin(A/2))`
`implies delta_(m)=2sin^(-1)(musin(A/2))-A`
Substituting `mu` = 1.5 and `A = 60^@`, we get
`delta_(m)=2sin^(-1)(0.75)-60^@=37^@`
Maximum deviation:
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