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Two beams of light having intensities I and 4I interferer to produce a fringe pattern on a screen.The phase difference between the beam is `pi/2` at point Aand `2pi` at point B. Then find out the difference between the resultant intensities at A and B.

Text Solution

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Resultant intensity `I=I_(1) + I_(2) + 2sqrt(I_(1))sqrt(I_(2)) cos phi`
Resultant intensity at point A is `I_(A)=I_(1) + 4I + 2sqrt(I_(1))sqrt(4I) cos(pi/2)=5I`
Resultant intensity at point B is `I_(B)=I+4I + 2sqrt(I) sqrt(4I) cos 2pi=9I`(`therefore cos2pi=1`)
`therefore I_(B)-I_(A) = 9I-5I implies =4I`
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