y sin y-cot x+xy^(2)=5

If x and y are the real numbers satisfying the equation 12sin x+5cos x=2y^(2)-8y+21 then the value of 12cot((xy)/(2)) is:

cos (x + y), sin (x + y), - cos (x + y) sin (xy), cos (xy), sin (xy) sin2x, 0, sin2y] | = sin2 (x + y)

y = ((sin x + x ^ (2)) / (cot2x))

If cos x+cos y+cos alpha=0 and sin x+sin y+sin alpha=0, then cot ((x+y)/(2))

If cot theta = cos (x+y) "and" cot phi = cos (x-y), "show that" tan (theta- phi)=(2sin x sin y )/(cos^(2) x + cos^(2) y)

If sin (xy) + (x)/(y) =x^(2) - y , " then " (dy)/(dx) is equal to

If sin (xy) + (x)/(y) =x^(2) - y , " then " (dy)/(dx) is equal to

Add : 4x^(2)y, - 3xy^(2), -5xy^(2), 5x^(2)y