[" (ii) "quad 2x+3y=8],[x-2y+3=0]

Solve [2x+3y-7=0],[3x+2y-8=0]

3x+2y=8 2x-3y=8

3x+2y=8 2x-3y=1

Solve: 2x+3y=2; x-2y=8

Solve for x and y: 2x - 3y-13 =0 , 3x -2y+12 =0

find x and y : 2x+3y-8=0, 3x+y-5=0

The area of the parallelogram formed by the lines 2x-3y+a=0, 3x-2y-a=0, 2x-3y+3a=0 and 3x-2y-2a=0 in square units , is