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The first and second I.E. of Mg are 750 ...

The first and second I.E. of Mg are 750 and 1450 kJ/mole respectively. What will be the ratio of `Mg^+ and Mg^(2+)` ions, if one mole magnesium vapours are supplied 1200 kJ of energy?

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To solve the problem, we need to determine the ratio of \( \text{Mg}^+ \) and \( \text{Mg}^{2+} \) ions when 1 mole of magnesium vapor is supplied with 1200 kJ of energy. We will use the given ionization energies to find out how many moles of each ion are produced. ### Step-by-Step Solution: 1. **Identify Ionization Energies**: - The first ionization energy (I.E.1) of Mg is 750 kJ/mole. - The second ionization energy (I.E.2) of Mg is 1450 kJ/mole. ...
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