A bird in air is at a height ‘y’ from the surface of water. A fish is at a depth ‘x’ below the surface of water. The apparent distance of fish from the bird is (The refractive index of water is n )

An under water swimmer is at a depth of 12 m below the surface of water. A bird is at a height of 18 m from the surface of water, directly above his eyes. For the swimmer the bird appears to be at a distance from the surface of water equal to (Refractive Index of water is 4/3)

A bird in air looks at a fish vertically below it and inside water. h_(1) is the height of the bird above the surface of water and h_(2) , the depth of the fish below the surface of water. If refractive index of water with respect to air be mu , then the distance of the fish as observed by the bird is

In a pond of water, a flame is held 2 m above the surface of the water. A fish is at depth of 4 m from the water surface. Refractive index of water is (4)/(3) . The apparent height of the flame from the eyes of fish is -

A plane mirror is fixed at the bottom of a vessel as shown in the figure. Water of refractive index mu is filled up to a height h in the vessel. There is a fish at a height h//2 from bottom of vessel and there is a bird at a height h above the surface of water in the vessel. (a) Calculate apparent distance of bird as seen by the fish. (b) Calculate apparent distance of image of bird in mirror as seen by the fish. (c) Calculate apparent distance of fish as seen by the bird. (d) Calculate apparent distance of image of fish in the mirror as seen by the bird.

A bird is flying 3m above the surface of water. To a fish underwater, the height of the bird from the water surface appears to be

A point source is placed at a depth h below the surface of water (refractive index = mu ). The medium above the surface of water is air from water.

A fish in water sees an object which is 24cm above the surface of water. The height of the object above the surface of water that will appear to the flash is (mu=4//3)