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Factories : 64a^(2)+96ab+36b^(2)...

Factories : `64a^(2)+96ab+36b^(2)`

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To factor the expression \(64a^2 + 96ab + 36b^2\), we can follow these steps: ### Step 1: Identify the coefficients and terms The given expression is \(64a^2 + 96ab + 36b^2\). Here, we have: - The coefficient of \(a^2\) is \(64\), - The coefficient of \(ab\) is \(96\), - The coefficient of \(b^2\) is \(36\). ### Step 2: Recognize perfect squares We can recognize that: - \(64a^2\) can be expressed as \((8a)^2\), - \(36b^2\) can be expressed as \((6b)^2\). ### Step 3: Check the middle term Now, we need to check if the middle term \(96ab\) fits the identity for a perfect square trinomial, which is of the form \(A^2 + 2AB + B^2\). Here, we can set: - \(A = 8a\), - \(B = 6b\). Now, we calculate \(2AB\): \[ 2AB = 2 \cdot (8a) \cdot (6b) = 96ab. \] This matches our middle term. ### Step 4: Write the expression as a square Since the expression fits the form \(A^2 + 2AB + B^2\), we can write it as: \[ (8a + 6b)^2. \] ### Final Answer Thus, the factorization of \(64a^2 + 96ab + 36b^2\) is: \[ (8a + 6b)^2. \] ---
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