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If the points A(4,6) and B(1,3) lie on ...

If the points A(4,6) and B(1,3) lie on the graph of ax +by =8 then find the value of a and b

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To solve the problem, we need to find the values of \( a \) and \( b \) such that the points \( A(4,6) \) and \( B(1,3) \) lie on the line represented by the equation \( ax + by = 8 \). ### Step 1: Substitute Point A into the Equation We start by substituting the coordinates of point \( A(4, 6) \) into the equation \( ax + by = 8 \). \[ a(4) + b(6) = 8 \] This simplifies to: \[ 4a + 6b = 8 \quad \text{(Equation 1)} \] ### Step 2: Substitute Point B into the Equation Next, we substitute the coordinates of point \( B(1, 3) \) into the same equation. \[ a(1) + b(3) = 8 \] This simplifies to: \[ a + 3b = 8 \quad \text{(Equation 2)} \] ### Step 3: Solve the System of Equations Now, we have a system of equations: 1. \( 4a + 6b = 8 \) (Equation 1) 2. \( a + 3b = 8 \) (Equation 2) We can solve these equations simultaneously. Let's first multiply Equation 2 by 4 to align the coefficients of \( a \): \[ 4(a + 3b) = 4(8) \] This gives us: \[ 4a + 12b = 32 \quad \text{(Equation 3)} \] ### Step 4: Subtract Equation 1 from Equation 3 Now, we subtract Equation 1 from Equation 3: \[ (4a + 12b) - (4a + 6b) = 32 - 8 \] This simplifies to: \[ 6b = 24 \] ### Step 5: Solve for \( b \) Now, we can solve for \( b \): \[ b = \frac{24}{6} = 4 \] ### Step 6: Substitute \( b \) Back to Find \( a \) Now that we have \( b = 4 \), we can substitute this value back into Equation 2 to find \( a \): \[ a + 3(4) = 8 \] This simplifies to: \[ a + 12 = 8 \] So, \[ a = 8 - 12 = -4 \] ### Final Values Thus, the values of \( a \) and \( b \) are: \[ a = -4, \quad b = 4 \] ### Summary The final answer is: - \( a = -4 \) - \( b = 4 \)
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