CBSE COMPLEMENTARY MATERIAL|Exercise PRACTICE TEST|3 Videos
Similar Questions
Explore conceptually related problems
The base BC of Delta ABC is divided at D, so that BD=(1)/(2)DC. Prove that ar(Delta ABD)=(1)/(3)ar(Delta ABC)
D is a point on the base BC of Delta ABC.AD is produced upto E such that DE = AD. Prove that: area of Delta BCE = " area of " Delta ABC
ABCD is a trapezium in which AB I I DC. DC is produced to E such tha t CE= AB, prove that ar( Delta ABD) = ar( Delta BCE).
In the given figure, Delta ABC and Delta DBC have the same base BC. If AD and BC intersect at O, prove that (ar(DeltaABC))/(ar(Delta DBC))=(AO)/(DO)
Diagonals AC and BD of a trapezium ABCD with AB || DC intersect each other at O. Prove that ar( Delta AOD) = ar( Delta BOC).
In Delta ABC,AD and BE are altitudes.Prove that (ar(Delta DEC))/(ar(Delta ABC))=(DC^(2))/(AC^(2))
In the same figure, Delta ABC and Delta DBC are on the same base BC . If AD is intersects BC at O, prove that (ar(Delta ABC))/(ar (Delta DBC))=(AO)/(DO)
ABCD is a trapezium with AB||DC. A line parallel to AC intersects AB at X and BC at Y. Prove that ar( Delta ADX) = ar( Delta ACY).
In figure ,D and E are Points on side BC of a Delta ABC such that BD=CE and AD=AE.Show that Delta ABD cong Delta ACE.
In the given figure,Delta ABC and Delta DBC are on the same base BC.If AD intersects BC at O , prove that (ar(Delta ABC))/(ar(Delta DBC))=(AO)/(DO)
CBSE COMPLEMENTARY MATERIAL-AREAS OF PARALLELOGRAMS AND TRIANGLES-PRACTICE TEST
