Home
Class 9
MATHS
The base of a right angled triangle is 4...

The base of a right angled triangle is `48 cm` and its hypotenuse is `50 cm` then its area is

A

`150cm^(2)`

B

`336cm^(2)`

C

`300cm^(2)`

D

`475cm^(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the area of the right-angled triangle with a base of 48 cm and a hypotenuse of 50 cm, we can follow these steps: ### Step 1: Identify the sides of the triangle Given: - Base (BC) = 48 cm - Hypotenuse (AC) = 50 cm Let the height (AB) be the unknown side we need to find. ### Step 2: Apply the Pythagorean theorem According to the Pythagorean theorem: \[ AC^2 = AB^2 + BC^2 \] Substituting the known values: \[ 50^2 = AB^2 + 48^2 \] ### Step 3: Calculate the squares Calculating the squares: \[ 50^2 = 2500 \] \[ 48^2 = 2304 \] ### Step 4: Rearrange the equation Now, substituting the squares back into the equation: \[ 2500 = AB^2 + 2304 \] To find \( AB^2 \), rearrange the equation: \[ AB^2 = 2500 - 2304 \] ### Step 5: Perform the subtraction Calculating the right side: \[ AB^2 = 196 \] ### Step 6: Find the height (AB) To find \( AB \), take the square root of both sides: \[ AB = \sqrt{196} = 14 \text{ cm} \] ### Step 7: Calculate the area of the triangle Now that we have both the base and height, we can calculate the area using the formula for the area of a triangle: \[ \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \] Substituting the values: \[ \text{Area} = \frac{1}{2} \times 48 \times 14 \] ### Step 8: Perform the multiplication Calculating the area: \[ \text{Area} = \frac{1}{2} \times 672 = 336 \text{ cm}^2 \] Thus, the area of the triangle is **336 cm²**. ---
Promotional Banner

Topper's Solved these Questions

  • HERON'S FORMULA

    CBSE COMPLEMENTARY MATERIAL|Exercise PART B|8 Videos
  • HERON'S FORMULA

    CBSE COMPLEMENTARY MATERIAL|Exercise PART C|7 Videos
  • CONSTRUCTIONS

    CBSE COMPLEMENTARY MATERIAL|Exercise QUESTIONS|7 Videos
  • INTRODUCTION TO EUCLID'S GEOMETRY

    CBSE COMPLEMENTARY MATERIAL|Exercise PRACTICE TEST|8 Videos

Similar Questions

Explore conceptually related problems

The base of a right angled triangle is 8 cm and hypotenuse is 17 cm . Find its area.

The perimeter of a right angled triangle is 24 cm. If its hypotenuse is 10 cm then area of this triangle is

The base of a right triangle is 48 cm and its hypotenuse is 50 cm long. The area of the triangle is

The difference between altitude and base of a right angled triangle is 17cm and its hypotenuse is 25cm.18. What is the sum of the base and altitude of the triangle is? (A) (C) 31cm24cm34cm D) None of these

The base of a right-angled triangle measures 48 cm and its hypotenuse measures 50 cm. Find the area of the triangle.

The base of a right - angled triangle measures 48 cm and its hypotenuse measures 50 cm . Find the area of the triangle .

The perimeter of a right angled triangle is 12 cm . The hypotenuse is 5 cm , then the area of the triangle is