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The number of planks of dimension (4mxx5...

The number of planks of dimension (`4mxx50cmxx20cm`) that can be stored in a pit which is 16m long, 12m wide and 4m deep is.

A

1900

B

1920

C

1800

D

1840

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of how many planks can be stored in a pit, we need to follow these steps: ### Step 1: Convert all dimensions to the same unit The dimensions of the planks are given as: - Length (L) = 4 m - Breadth (B) = 50 cm - Height (H) = 20 cm We will convert the length of the planks from meters to centimeters: - \( L = 4 \, \text{m} = 4 \times 100 = 400 \, \text{cm} \) Now, the dimensions of the planks in centimeters are: - Length = 400 cm - Breadth = 50 cm - Height = 20 cm ### Step 2: Calculate the volume of one plank The volume (V) of one plank can be calculated using the formula: \[ V = L \times B \times H \] Substituting the values: \[ V = 400 \, \text{cm} \times 50 \, \text{cm} \times 20 \, \text{cm} \] \[ V = 400 \times 50 \times 20 = 400000 \, \text{cm}^3 \] ### Step 3: Determine the dimensions of the pit The dimensions of the pit are given as: - Length = 16 m - Width = 12 m - Depth = 4 m We will convert these dimensions to centimeters: - Length = \( 16 \, \text{m} = 16 \times 100 = 1600 \, \text{cm} \) - Width = \( 12 \, \text{m} = 12 \times 100 = 1200 \, \text{cm} \) - Depth = \( 4 \, \text{m} = 4 \times 100 = 400 \, \text{cm} \) ### Step 4: Calculate the volume of the pit The volume of the pit can be calculated using the formula: \[ V_{\text{pit}} = \text{Length} \times \text{Width} \times \text{Depth} \] Substituting the values: \[ V_{\text{pit}} = 1600 \, \text{cm} \times 1200 \, \text{cm} \times 400 \, \text{cm} \] \[ V_{\text{pit}} = 1600 \times 1200 \times 400 = 768000000 \, \text{cm}^3 \] ### Step 5: Calculate the number of planks that can fit in the pit Let \( n \) be the number of planks that can fit in the pit. The total volume of the planks must equal the volume of the pit: \[ n \times V_{\text{plank}} = V_{\text{pit}} \] Substituting the volumes: \[ n \times 400000 \, \text{cm}^3 = 768000000 \, \text{cm}^3 \] To find \( n \): \[ n = \frac{768000000}{400000} \] \[ n = 1920 \] ### Final Answer The number of planks that can be stored in the pit is **1920**. ---
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