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A letter is chosen at random from Englis...

A letter is chosen at random from English alphabets. The probability of that letters pf the word CYLINDER is .

A

`4//13`

B

`13//4`

C

`2//13`

D

`13//2`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the probability of choosing a letter from the word "CYLINDER," we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Sample Space**: The sample space consists of all the letters in the English alphabet. There are a total of 26 letters in the English alphabet. **Hint**: Remember that the English alphabet consists of letters from A to Z. 2. **Identify the Unique Letters in "CYLINDER"**: Next, we need to identify the unique letters in the word "CYLINDER". The letters are C, Y, L, I, N, D, E, R. **Hint**: Count each letter only once, even if it appears multiple times in the word. 3. **Count the Unique Letters**: The unique letters in "CYLINDER" are C, Y, L, I, N, D, E, R, which gives us a total of 8 unique letters. **Hint**: List out the letters to ensure you count them correctly. 4. **Calculate the Probability**: The probability of choosing a letter from "CYLINDER" when a letter is chosen at random from the English alphabet can be calculated using the formula: \[ P(E) = \frac{N(E)}{N(S)} \] where \(N(E)\) is the number of favorable outcomes (unique letters in "CYLINDER") and \(N(S)\) is the total number of outcomes (total letters in the English alphabet). Here, \(N(E) = 8\) and \(N(S) = 26\). So, the probability \(P(E)\) is: \[ P(E) = \frac{8}{26} \] 5. **Simplify the Probability**: We can simplify \(\frac{8}{26}\) by dividing both the numerator and the denominator by 2: \[ P(E) = \frac{4}{13} \] ### Final Answer: The probability of choosing a letter from the word "CYLINDER" is \(\frac{4}{13}\). ---
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