The polynomial of type `ax^(2)+bx+c`, when a=0

Options

A. Linear
B. Quadratic
C. Cubic
D. Biquadratic

Answer

To solve the question, we need to analyze the polynomial given in the form \( ax^2 + bx + c \) when \( a = 0 \).

### Step-by-Step Solution:

1. **Identify the Polynomial**:
The polynomial is given as \( ax^2 + bx + c \).

2. **Substitute \( a = 0 \)**:
When we set \( a = 0 \), the polynomial simplifies to:
\[ 0 \cdot x^2 + bx + c = bx + c \]

3. **Determine the Type of Polynomial**:
The simplified polynomial \( bx + c \) is a linear polynomial. This is because it is in the form \( mx + b \), where \( m \) is the coefficient of \( x \) (which is \( b \) in this case), and there is no \( x^2 \) term.

4. **Identify the Degree**:
The degree of the polynomial \( bx + c \) is 1, since the highest power of \( x \) present is 1.

5. **Conclusion**:
Since the degree of the polynomial is 1, it is classified as a linear polynomial.

### Final Answer:
The polynomial \( ax^2 + bx + c \) when \( a = 0 \) is a **linear polynomial**.