The potential energy of a body is given by `U=9/x^(2)-2/x` The position at which its speed can be maximum is.

The potential energy of a body is given by U = A - Bx^(2) (where x is the displacement). The magnitude of force acting on the partical is

The potential energy of a body is given by U = A - Bx^(2) (where x is the displacement). The magnitude of force acting on the partical is

The potential energy of a body of mass m is given by U=ax+by where x,y are position co-ordinate of the particle. The acceleration of the particle is

The potential energy U of a body of mass m is given by U = ax + by where x and y are the position coordinates of the particle, the net force acting on the particle is:

The potential energy of a particle is given by formula U=100-5x + 100x^(2), where U and are .

Potential energy of a particle at position x is given by U=x^(2)-5x . Which of the following is equilibrium position of the particle?

Potential energy of a particle at position x is given by U=x^(2)-5x . Which of the following is equilibrium position of the particle?