If `z=x+i y` , then he equation `|(2z-i)//(z+1)|=m` represents a circle, then `m` can be `1//2` b. `1` c. `2` d. `3

If z=x+i y , then he equation |(2z-i)/(z+1)|=m represents a circle, then m can be (a) 1/2 b. 1 c. 2 d. 3

If z=x+iy, then he equation |(2z-i)/(z+1)|=m represents a circle,then m can be (1)/(2) b.1 c.2d.3

If z=x+i y , then the equation |(2z-i)/(z+1)|=m does not represents a circle, when m is (a) 1/2 (b). 1 (c). 2 (d). 3

If z=x+i y , then the equation |(2z-i)/(z+1)|=m does not represents a circle, when m is (a) 1/2 (b). 1 (c). 2 (d). 3

If z=x+iy, where i=sqrt(-1) , then the equation abs(((2z-i)/(z+1)))=m represents a circle, then m can be

If z=x+iy, where i=sqrt(-1) , then the equation abs(((2z-i)/(z+1)))=m represents a circle, then m can be

Q.2 The equation |z+1-i|=|z+i-1| represents a

If z=x+iy, where i=sqrt(-1) , then the equation abs(((2z-i)/(z+i)))=m represents a circle, then m can be

The equation |((1+i)z-2)/((1+i)z+4)|=k does not represent a circle when k is

If z in C then |(2z-i)/(5z+1)|=m,m in R represents a straight line if