The position vector of four points A, B, C and D are a,b,c and d respectively . If a- b = 2(d-c) the

The position vectors of four points A,B,C,D lying in plane are a,b,c,d respectively.They satisfy the relation |a-d|-|b-d|-|c-d| ,then the point D is

vec a,vec b,vec c,vec d are the position vectors of the four distinct points A,B,C, D respectively.If vec b-vec a=vec c-vec d, then show that ABCD is a parallelogram.

The position vectors of four points A, B, C and D in the plane are vec(a),vec(b),vec( c ) and vec(d) . If (vec(a)-vec(d)).(vec(b)-vec( c ))=(vec(b)-vec(d)).(vec( c )-vec(a))=0 then D is a ………………is DeltaABC .

If vec a , vec b , vec c , vec d are the position vector of point A , B , C and D , respectively referred to the same origin O such that no three of these point are collinear and vec a + vec c = vec b + vec d , than prove that quadrilateral A B C D is a parallelogram.

If vec a , vec b , vec c , vec d are the position vector of point A , B , C and D , respectively referred to the same origin O such that no three of these point are collinear and vec a + vec c = vec b + vec d , than prove that quadrilateral A B C D is a parallelogram.

If vec a , vec b , vec c , vec d are the position vector of point A , B , C and D , respectively referred to the same origin O such that no three of these point are collinear and vec a + vec c = vec b + vec d , than prove that quadrilateral A B C D is a parallelogram.

If vec a , vec b , vec c , vec d are the position vector of point A , B , C and D , respectively referred to the same origin O such that no three of these point are collinear and vec a + vec c = vec b + vec d , than prove that quadrilateral A B C D is a parallelogram.