In parallelogram ABCD, E is the mid-point of side AB and CE bisects angle BCD. Provethat:(i) AE=AD(i) DE bisects `/_ADC` and(ili) Angle DEC is a right angle.

In parallelogram ABCD, E is the mid-point of side AB and CE bisect angle BCD. Prove that : (i) AE=AD (ii) DE bisect angleADC and (iii) Angle DEC is a right angle.

ABCD is a parallelogram E is the mid point of AB and CE bisects angleBCD . Prove that: AE=AD?

ABCD is a parallelogram E is mid-point of AB and DE bisects angle D. Prove that BC= BE

ABCD is a parallelogram E is the mid point of AB and CE bisects angleBCD . Prove that: angleDEC=90^@

ABCD is a parallelogram E is the mid point of AB and CE bisects angleBCD . Prove that: DE bisects angleADC

ABCD is a parallelogram, E is the mid-point of AB and CE bisects angleBCD . Then angleDEC is

ABCD is a parallelogram E is mid-point of AB and DE bisects angle D. Prove that angleDEC= 90^(@)

ABCD is a parallelogram E is mid-point of AB and DE bisects angle D. Prove that CE bisects angle C

If ABCD is a parallelogram,E is the mid-point of AB and CE bisects /_BCD, then /_DEC is

In a parallelogram ABCD, the bisector of angleA bisects the line B at point X. Prove that AD = 2AB.