3x-8y=3;x=3y

Solve for x and y - 2x+3y-8=0 3x+4y-5=0

find x and y : 2x+3y-8=0, 3x+y-5=0

5x-3y=8,3x+y=2 .

27x^3+8y^3=(3x+2y)…………..

Simplify : 7x^3 +8y^3- (4x+3y)(16x^2-12xy+9y^2)

Factorise : (2x-3y)^3-(8x^3-27y^3)

Simplify the following: 7x^3+8y^3-(4x+3y)(16 x^2-12 x y+9y^2)

Find the value of 27x^(3)+8y^(3), if 3x+2y=14 and xy=83x+2y=20 and xy=(14)/(9)

If (-2,\ 1) is the centroid of the triangle having its vertices at (x ,\ 0),\ (5,\ -2),\ (-8,\ y), then x ,\ y satisfy the relation 3x+8y=0 (b) 3x-8y=0 (c) 8x+3y=0 (d) 8x=3y

If (-2,1) is the centroid of the triangle having its vertices at (x,0),(5,-2),(-8,y), then x,y satisfy the relation 3x+8y=0 (b) 3x-8y=0( c) 8x+3y=0 (d) 8x=3y