A particle is moving in a straight line. At time `t` the distance between the particle from its starting point is given by `x=t-6t^(2)+t^(3)`. Its acceleration will be zero at

A particle is moving in a straight line. At time, the distance between the particle from its starting point is given by x=t-6t^(2)+t^(3) . lts acceleration will be zero at

A particle is moving in a straight line. At time t, the distance between the particle from its starting point is given by x =t- 9t^(2) + t^(3) . lts acceleration will be zero at

A particle is moving in a straight line its displacement at any instant t is given by x=5t^(2)+20t^(3) . Find the average acceleration in the interval t = 0 to t = 3 seconds.

If the distance from the initial point at a time t is given by x = t - 6t^2 + t^3 : then at what time the acceleration will be zero?

If the distance S travelled by a particle in time t is given by s = t^(2) - 2t + 5 then its acceleration is

For a particle moving in a straight line, the displacement of the particle at time t is given by S=t^(3)-6t^(2) +3t+7 What is the velocity of the particle when its acceleration is zero?

For a particle moving in a straight line, the displacement of the particle at time t is given by S=t^(3)-6t^(2) +3t+7 What is the velocity of the particle when its acceleration is zero?

For a particle moving in a straight line, the displacement of the particle at time t is given by S=t^(3)-6t^(2) +3t+7 What is the velocity of the particle when its acceleration is zero?

If a particle moving in a straight line and its distance x cms from a fixed point O on the line is given by x=sqrt(1+t^(2)) cms, then acceleration of the particle at t sec. is

The distance s of a particle in time t is given by s=t^3-6t^2-4t-8 . Its acceleration vanishes at t=