" 10."f(x)={[x-1,," when "1<=x<2;],[2x-3,," when "2<=x<=3]" is continuous at "x=2

If f(x)={{:(3x-1" when "xle0),(x+1" when "xgt0):} , find f(-1) and f(0).

If f(x)={{:(2x-1,"when "xle0),(x^(2),"when "xgt0):},"then find "f((1)/(2)) and f((-1)/(2))

If f (x) ={{:(x",", "when " 0 lt x lt 1),(2-x",", "when" 1 lt x le 2):} then f'(1) is equal to-

A function f(x) is defined as follows : f(x)=x," when "x lt1 =x+1," when "x gt1 =3/2," when "x=1 Draw the graph of f(x) and examine its continuity at x=(1)/(2)and x=1.

A function f (x) is defined as follwos : f(x){:(=2x+1," when "xle 1),(= 3-x," when "xgt1):} Examine whether underset(xrarr1)"lim"f(x) exists or not.

If f(x)=x^(2)+1, when x!=1 and f(x)=3 when x=1, prove that f(x) is not continuous at x=1.

If f(x)=3x-1 when x geq1 and f(x) = -x when x lt 1 then value of f(-2) is

If f(x) = 3x-1 when x geq 1 and f(x) = -x when x lt 1 then value of f(-2) is