`x^2+1/x^2 -2 -3x +3/x`

Foctorise : x^(2) +(1)/(x^(2)) - 2 -3 x+ (3)/(x)

Find the sum of n-terms of the following series: (x+1/x)^2+(x^2+1/x^2)^2+(x^3+1/x^3)^2+(x^4+1/x^4)^2+...

If x^2-x+1 =0 then find the value of (x+1/x)^2+(x^2+1/x^2)^2+(x^3+1/x^3)^2+...+(x^24+1/x^24)^2 .

The sum of 10 terms of the series (x+1/x)^2+(x^2+1/x^2)^2+(x^3+1/x^3)^2+.... is

If x is real and Delta(x)=|[x^2+x, 2x-1, x+3] , [3x+1, 2+x^2, x^2-3] , [x-3, x^2+4, 2x]|= a_0x^7+a_1x^6+a_2x^5+...+a_6x+a_7 then

Find the sum to n terms of the series : (x+1/x)^2+(x^2 + 1/x^2)^2+ (x^3 + 1/x^3)^2+ ...... .

If |{:(x^(2) +x , 3x - 1 , -x + 3),(2x +1 , 2 + x^(2) , x^(3) - 3),(x - 3, x^(2) + 4, 3x):}| = a_(0) + a_(1) x + a_(2) x^(2) + .... + x_(7) x^(7), then the value of a_(0) is

Evaluate lim_(x to 2) [(1)/(x - 2) - (2(2x - 3))/(x^(3) - 3x^(2) + 2x)]