[2x+y=5" fasiver "],[xx+2y=8" ara "]

Solve : 5^(x)= 25 xx 5 ^(y) and 8 xx 2 ^(y) = 4 ^(x)

(a) 2x+y=5 ; 3x+2y=8

2x+8y+5z=5 x+y+z=-2 x+2y-z=2

If the circumference of the circle x^2+y^2+8x+8y-b=0 is bisected by the circle x^2+y^2=4 and the line 2x+y=1 and having minimum possible radius is 5x^2+5y^2+18 x+6y-5=0 5x^2+5y^2+9x+8y-15=0 5x^2+5y^2+4x+9y-5=0 5x^2+5y^2-4x-2y-18=0

Solve by matrix method : x + 2y = 5, y + 2z = 8, z +2x = 5.

x+2y=3 2x-y=8.5 If (x, y) is a solution to the above system of equtions, what is the value of x-y ?

Maximize z = 5x + 7y such that 2x + y ge 8, x + 2y ge 10 x, y ge 0 .

If 2x +3y = 30 and (x+y)/y = 11/8 , then find the value of 5y + 6x

For hyperbola whose center is at (1,2) and the asymptotes are parallel to lines 2x+3y=0 and x+2y=1, the equation of the hyperbola passing through (2,4) is (2x+3y-5)(x+2y-8)=40(2x+3y-8)(x+2y-8)=40(2x+3y-8)(x+2y-5)=30 these