[" In triangle "ABC,/_B=pi/3," and "/_C=pi/4." Let "D" divide "BC" inernally in the ratio "1:3." Then "],[sin/_BAD],[sin/_CAD]

In triangle ABC,/_B=(pi)/(3), and /_C=(pi)/(4)* Let D divided BC internally in the ratio 1:3. Then (sin/_BAD)/(sin/_CAB) equals (a) (1)/(sqrt(6)) (b) (1)/(3)(c)(1)/(sqrt(3)) (d) sqrt((2)/(3))

In triangle A B C ,/_B=pi/3,a n d/_C=pi/4dot Let D divided B C internally in the ratio 1: 3. Then (sin/_B A D)/(sin/_C A D) equals (a) 1/(sqrt(6)) (b) 1/3 (c) 1/(sqrt(3)) (d) sqrt(2/3)

In triangle A B C ,/_B=pi/3,a n d/_C=pi/4dot Let D divided B C internally in the ratio 1: 3. Then (sin/_B A D)/(sin/_C A B) equals (a) 1/(sqrt(6)) (b) 1/3 (c) 1/(sqrt(3)) (d) sqrt(2/3)

In a triangle ABC, angleB = pi/3 and angleC= pi/4 . Let D divide side BC internally in the ratio 1:3. Then sin(angleBAD)/sin(angleCAD) is

In triangle ABC, angle B = pi//3. " and " angle C = pi//4 . Let D divide BC inernally in the ratio 1 : 3 . Then (sin angle BAD)/(sin angle CAD) equals

In a triagnle ABC, angle B=pi/3 " and " angle C = pi/4 let D divide BC internally in the ratio 1:3 .Then (sin (angle BAD))/((Sin (angle CAD)) is equal to

In a triagnle ABC, angle B=pi/3 " and " angle C = pi/4 let D divide BC internally in the ratio 1:3 .Then (sin (angle BAD))/((Sin (angle CAD)) is equal to

In a Delta ABC,/_B=60^(@) and /_C=45^(@). Let D divides BC internally in the ratio 1:3. then value of (sin/_BAD)/(sin/_CAD) is (A) sqrt((2)/(3)) (B) (1)/(sqrt(3)) (C) (1)/(sqrt(6)) (D) (1)/(3)