" 11."sin m theta=sin n theta

5. sin m theta=sin n theta

cos m theta-sin n theta=0

Solve that equation : sin m theta+sin n theta=0

If cos m theta = sin n theta , then theta =

Prove that , sin theta + sin 2theta + ……+ sin n theta = ( (sin( n theta/(2)) sin ((n+1)/(2))theta))/(sin theta/2) , for all n in N .

(sin4 theta+sin5 theta)/(cos3 theta+1)=sin(m theta)+sin(n theta) where m,n in N, then (m+n) equals.

cos m theta=sin n theta then theta=

Prove that sin^2 theta+sin^2 2theta+sin^2 3theta+....+sin^2 n theta=n/2-(sin n theta cos(n+1)theta)/(2sin theta)

sin ((theta) / (2)) sin ((7 theta) / (2)) + sin ((3 theta) / (2)) sin ((11 theta) / (2)) = sin (2 theta) sin (5 theta)