`7(x-2y)^2 - 25 (x-2y)+12`

Factorise : (x-2y)^(2) - 12(x-2y) + 32

Factorise: 25(x+y)^(2)- 36 (x-2y)^(2).

If x^2+y^2 = 25 and xy = 12, then the value of x^(-1)+y^(-1) is :

The circles x^2 + y^2 + 6x + 6y = 0 and x^2 + y^2 - 12x - 12y = 0

Factor (x + y) ^ (2) -7 (x ^ (2) -y ^ (2)) + 12 (xy) ^ (2)

{:("Column" A ,, "Column" B), (225x^(2) - 625 y^(2) = ,, (a) 25(x-2) (x-2)), (x^(2) - x - y - y^(2) = ,, (b) 25(3x- 5y) (3x + 5y)), (x^(2) - x - y^(2) + y = ,, (x + y) (x - y- 1)), (25x^(2) - 100 x + 100 = ,, (d) (x - y) (x + y -1)), (,,(e) (x + y) (x + y - 1)):}

Divide: 25 x^3y^2\ by -15 x^2y (ii) -72 x^2y z\ by -12 x y z

Add the algebraic expressions: 4x y^2-7x^2y ,\ 12 x^2y-6x y^2,\ -3x^2y+5x y^2