4^(n)+15n-1" 거식 "9-9.5" '彡िण्ल "

By the Principle of Mathematical Induction, prove the following for all n in N : 4^(n)+ 15n-1 is divisible by 9.

Prove the following by using the Principle of mathematical induction AA n in N 4^(n) +15n-1 is divisble by 9.

Prove by the principle of mathematical induction 4^(n)+ 15n - 1 is divisible 9 for all n in N .

For every natural number n(gt1) , show that , 4^(n)+15n-1 is divisible by 9 .

For all ninNN , prove by principle of mathematical induction that, 4^(n)+15n-1 is a multiple of 9.

Using the principle of mathmatical induction, prove each of the following for all n in N (4^(n)+15n-1) is divisible by 9.

By Mathematical Induction, prove the following: (i) (4^(n) + 15n - 1) is divisible by 9, (ii) (12^(n) + 25^(n – 1)) is divisible by 13 (iii) 11^((n + 2)) + 12^((2n + 1)) is divisible by 133 for all ninN

4^(n+1) + 15n + 14 is divisible by 9 for every natural number n ge 0 .

By Mathematical Induction, prove the following : (4^n+ 15n -1) is divisible by 9 .

lim_ (n rarr oo) (7.3 ^ (n + 1) + 3.5 ^ (n + 1)) / (5.3 ^ (n) -9.5 ^ (n))