`1/3 x^2 - 2x - 9`

int x^2 e^(3x) dx=............ A) (1/3) x^2 e^(3x) - (2/9) x e^(3x) + (2/27) e^(3x) + c B) -(1/3) x^2 e^(3x) - (2/9) x e^(3x) + (2/27) e^(3x) + c C) (1/3) x^2 e^(3x) + (2/9) x e^(3x) - (2/27) e^(3x) + c D) (1/3) x^2 e^(3x) - (2/9) x e^(3x) - (2/27) e^(3x) + c

Compute Lt_(x to 3) (x^2 - 9)/(x^3 - 6x^2 + 9x + 1)

The value of x satisfying abs(x-1)^(log_3 x^2-2log_x 9)=(x-1)^7 is

Fill in the blanks from the given options : (1)/(2) , 9 (6x - 9) (3x^(2) - 9x + 5)^(8), 49, -2, (1)/(2) [log(sin x)]^(2) + c, (1)/(x), 10 , onto (d)/(dx) [3x^(2) - 9x+5]^(9) = ………

4 (x + 1) / (2) + (x + 2) / (3) = (2x-5) / (7) +9

(3x - 9)/( (x - 1 )(x + 2 )(x^(2)+1))

Solve : (2x^2 - 3x+1) (2x^2 + 5x + 1) = 9x^2 .